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You are here: Home / What is Vedic Mathematics / Solving Equations/Expressions / (cont. )Equations – 2

(cont. )Equations – 2

August 16, 2013 by Rahul Bhangale Leave a Comment

Cyclic (General) Formula

This is a GENERAL formula of Vedic Mathematics which can be applied to any 2 equations for obtaining 2 unknown values.

Consider following 2 general equations
ax + by = p
cx + dy = q

Solving,
x = (bq – pd) / (bc – ad)
y = (cp – aq) / (bc – ad)

Notice that for calculation of numerators (x any y) cyclic method is used and Denominators remains same for both x and y.

Examples:
2x + 3y =6
3x + 4y = 3

Applying above formula:
x = (9 – 24)/ (9 – 8) = -15
y = (18 – 6) (9 – 8) = 12

-3x + 5y = 2
4x + 3y = -5

Applying above formula:
x = (-25 -6) / (20+9) = -31/29
y = (8-15) / (20+9) = -7/29

Sunyam Anyat

Sanskrit Name:

शून्यमन्यत्

English Translation:

If one is in ratio then other is 0.

Prerequisites:

Ratio of 1 of the variables should be = ratios of RHS.

Meaning:

If above condition is satisfied then other variable = 0.
The variable which was in ratio = Ratio of RHS and its corresponding coefficient.

Examples:

3x + 2y = 4
6x + 3y = 8

Here coefficients of (x) are in ratio 1:2 which is same as that of RHS.
So according the Sunyam Anyat, y= 0.
And x is calculated by taking the ratio of RHS and coeff i.e. 4/3 or 8/6. Hence x = 4/3.

12x + 8y = 7
16x + 16y = 14 Here coeff of y and RHS are in same ratio. So x = 0 and y = 7/8.

 

Sankalana Vyavakalanabhyam

Sanskrit Name:

संकलनव्यवकलनाभ्याम्

English Translation:

Addition and Subtraction.(Addition and Subtraction gives x+y and x-y expressions).

Prerequisites:

Coefficient of 1 variable in 1st equation should be same to other in 2nd equation (+/- matterless.)

Meaning:

If coefficient of 1 variable 1st equation is same as that of other in 2nd equation then Adding and Subtracting both the equations brings equations in the form of ‘x+y’ and ’x-y’ which can be EASILY solved simultaneously.

Examples:

2x + 3y = 5
3x + 2y = 6

Adding both Equations gives, 5x + 5y = 11. Hence x + y = 11/5.
Subtracting both equation gives, -x + y = -1
Now these 2 new equations can be EASILY solved simultaneously giving x = 8/5 and y = 3/5.

Similarly solve for 23x – 14y = 34 & 14x – 23y = 12.

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